Matematika

Pertanyaan

Nilai y yang memenuhi sistem persamaan:
4x+5y-2z=15
3x-2y+z=3
2x+y+3z=2

2 Jawaban

  • 4x+5y-2z=15 ..... (1)
    3x-2y+z=3 ...........(2)
    2x+y+3z=2 ...........(3)

    eliminasi (1) & (2)
    4x+5y-2z=15 ..... (dikali 3)
    3x-2y+z=3 ...........(dikali 4)
    ..
    12x - 15y - 6z = 45
    12x - 8y + 4z = 12
    --------------------------- --
    - 7y - 10z = 33 .........(4)

    elimimasi (2) dan (3)
    3x-2y+z=3 ...........( dikali 2)
    2x+y+3z=2 ...........(dikali 3)
    ..
    6x - 4y + 2z = 6
    6x + 3y + 9z = 6
    ------------------------- --
    - 7y - 7z = 0 ..........(5)

    eliminasi (4) dan (5)
    - 7y - 10z = 33
    - 7y - 7z = 0
    -------------------- --
    - 3z = 33
    z = 33 ÷ (-3)
    z = - 11

    substitusi z = - 11 ke - 7y - 10z = 33
    - 7y - 10(-11) = 33
    - 7y +110 = 33
    - 7y = 33 - 110
    - 7y = - 77
    y = -77 ÷ (-7)
    y = 11

    subatitusi z = - 11 dan y = 11 ke 4x+5y-2z=15
    4x + 5(11) - 2(-11) = 15
    4x + 55 + 22 = 15
    4x + 77 = 15
    4x = 15 - 77
    4x = - 62
    x = - 62 ÷ 4
    x = - 13

    jadi x = - 13, y = 11, z = - 11
  • 4x+5y-2z=15.......(1)
    3x -2y+z =3..........(2)
    2x+y+3z=2...........(3)

    eliminasi z dari pers.(1) dan (2)
    4x+5y-2z=15 |x1| 4x+5y-2z=15
    3x-2y+z=3     |x2| 6x-4y+2z=6   ~~~~~10x+y=21......(4)

    eliminasi z dari (2) dan (3)
    3x-2y+z=3  |x3| 9x-6y+3z=9
    2x+y+3z=2 |x1| 2x+t+3z  =2 ~~~~~7x-7y=7........(5)

    eliminasi y dari (4) dan (5)
    10x+y=21 |x7| 70x+7y=147
    7x-7y=7    |x1| 7x-7y=7 ~~~~~  77x=154
                                                          x=2

    substitusi pers.4
    10x+y  =21
    10(2)+y=21
    20+y    =21
               y=21-20
               y=1

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