mohon di bantu ya kawan-kawan

Segitiga Pascal
( a + b )^4 = a^4+4a^3b+6a^2b^2+4ab^3+b^4
(2x+3)^4 = (2x^2)^4 +4(2x^2)^3.3 +6(2x^2)^2.3^2 +4(2x^2).3^3 + 3^4
= 16x^8 +96x^6 +216x^4 +216x^2 +6561.