Matematika

Pertanyaan

nilai 5^log 2. 2^log 25 + 3^log 81

tolongggg kaka

2 Jawaban

  • 5log2. 2log5 + 3log81
    = log2/log5. log5/log2 + 3log3^4
    = 1 + 4
    = 5 ( kalau itu maksud soal )
  • 5log2 = log2 / log5 = 0,301 / 0,698 = 0,431
    2log25 = log25 / log2 = 1,397 / 0,301 = 4,641
    3log81 = log81 / log3 = 1,908 / 0,477 = 4

    0,431 x 4,641 + 4 = 6,000271

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