Diketahui fungsi kuadrat f(x)=3(x-1)²+5.Nilai a+b+c=
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Diketahui fungsi kuadrat f(x)=3(x-1)²+5.Nilai a+b+c=
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1. Jawaban arafahdira
[tex]f(x) = 3(x-1)^{2}+5 \\f(x) = 3 ( x^{2} -2x+1)+5 \\ f(x) = 3x^{2} -6x+3+5 \\ f(x) = 3x^{2} -6x+8[/tex]
[tex]a = f(x) \\ b = 3 (x-1)^{2} \\ c = 5 \\ a+b+c? \\ (f(x)) +(3 x^{2} -6x +3) + (5) \\ f(x) = 3x^{2} -6x+8 \\ ( 3x^{2}-6x+8) + ( 3x^{2} -6x+3) + (5) \\ 3x^{2} + 3x^{2} -6x-6x+8+3+5 \\ 6x^{2} +16[/tex]