Tentukan bentuk sederhana dari: (3√2 + 2√3) (√18 - √12)

Materi Bentuk Akar [tex] (3 \sqrt{2} + 2 \sqrt{3})(\sqrt{18} - \sqrt{12}) \\ = (3 \sqrt{2} + 2 \sqrt{3})(3\sqrt{2} - 2\sqrt{3}) \\ = (3\sqrt{2})^2 - (2 \sqrt{3})^2 \\ = 9 \times 2 - 4 \times 3 \\ = 18 - 12 = 6 [/tex]