integral (1-x) (1+x ) dx

Integral

∫ (1 - x)(1 + x) dx
= ∫ 1(1 - x) - x(1 + x) dx
= ∫ 1 - x + (-x - x²) dx
= ∫ 1 + (0 - x²) dx
= ∫ -x² + 1 dx
= - ∫ x² dx + ∫ 1 dx
= -1/3 x^3 + x + C