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Pertanyaan

hitunglah molaritas 0,5 gram glukosa C6H1206(Ar.C=12,H=1,0=16)DALAM 25 ML AIR

1 Jawaban

  • Dik : massa = 0,5 gr
    C6H12O6 Ar C = 12
    H = 1 , O = 16
    V = 25 ml
    Dit : M...?
    Mr = (6×12)+(12×1)+(6×16)
    = 72+12+96
    = 180
    M = gr/mr × 1000/v
    M = 0,5/180 × 1000/25
    M = 0,0027 × 40
    M = 0,108 M

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