hitunglah molaritas 0,5 gram glukosa C6H1206(Ar.C=12,H=1,0=16)DALAM 25 ML AIR
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Pertanyaan
hitunglah molaritas 0,5 gram glukosa C6H1206(Ar.C=12,H=1,0=16)DALAM 25 ML AIR
1 Jawaban
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1. Jawaban putrisheila08
Dik : massa = 0,5 gr
C6H12O6 Ar C = 12
H = 1 , O = 16
V = 25 ml
Dit : M...?
Mr = (6×12)+(12×1)+(6×16)
= 72+12+96
= 180
M = gr/mr × 1000/v
M = 0,5/180 × 1000/25
M = 0,0027 × 40
M = 0,108 M