tentukan volume 4,0 gram gas oksigen (Mr=32)pada keadaan normal 1 atm ,25 derajat celcius (1 atm=10pangkat5 Pa R= 8,3 J/MOL

TKG

m = 4 gr
Mr = 32 gr/mol
P = 10⁵ Pa
T = 25+273 = 298 K
V = __?

jumlah mol
n = m / Mr
n = (4 gr) / (32 gr/mol)
n = ⅛ mol


Pada keadaan RTP
1 mol = 24 L


V = (⅛ mol) • (24 L/mol)
V = 3 L = 3×10⁻³ m³ ← jwb

atau
P V = n R T
V = n R T / P
V = (⅛ mol) (8,314 J/(mol K) (297 K) / (10⁵ Pa)
V ≈ 3×10⁻³ m³ ← jwb