Pangkat 1/9 log 1/3.pangkat 27 log 49. Pangkat 1/7 log 1/81
Matematika
anjiang12
Pertanyaan
Pangkat 1/9 log 1/3.pangkat 27 log 49. Pangkat 1/7 log 1/81
1 Jawaban
-
1. Jawaban syifajs
Mata Pelajaran : Matematika Peminatan
Kelas : 10
Bab : 02 - Fungsi Logaritma
[tex] {}^{ \frac{1}{9} } log( \frac{1}{3} ) \times {}^{27} log(49) \times {}^{ \frac{1}{7} } log( \frac{1}{81} ) \\ = {}^{3 {}^{ - 2} } log(3 {}^{ - 1} ) \times {}^{27} log(49) \times {}^{ \frac{1}{7} } log( \frac{1}{81} ) \\ = \frac{1}{2} \times {}^{27} log(49) \times {}^{ \frac{1}{7} } log( \frac{1}{81} ) \\ = \frac{{}^{27} log(49) \times {}^{ \frac{1}{7} } log( \frac{1}{81} ) }{2} \\ = \frac{ {}^{3 {}^{3} log(7 {}^{2} ) \times {}^{7 {}^{ - 1} } log(3 {}^{ - 4} ) } }{2} \\ = \frac{ \frac{2}{3} \times {}^{3} log(7) \times 4. {}^{7} log(3) }{2} \\ = \frac{2}{3} \times {}^{3} log(7) \times 2. {}^{7} log(3) \\ = \frac{2}{3} \times 1 \times 2 \\ = \frac{4}{3} \\ atau \\ [/tex]
≈ 1 ⅓