Akar akar persamaan 2x pangkat 2 -3x-5=0

2x^2 - 3x - 5 = 0
(2x - 5)(x + 1) = 0

2x - 5 = 0
2x = 5
x = 5/2

x + 1 = 0
x = -1

Hp = { -1 , 5/2 }

0 = 2x^2 - 3x - 5
0 = ( 2x - 5 ) ( x + 1 )

0 = 2x - 5
5 = 2x
x = 5/2

0 = x + 1
-1 = x

HP : { -1 , 5/2 }