Matematika

Pertanyaan

[tex]|4x-3| \leq -\frac{27}{4} [/tex]

1 Jawaban

  • |4x-3|<= -27/4
    4x-3<= -27/4
    4x<= -27/4+3
    4x <= -27/4 + 3/1
    4x <= -27/4 + 12/4
    4x <= -15/4
    x <= -15/4 : 4
    x <= -15/16

    4x-3 >= 27/4
    4x >= 27/4 + 3
    4x >= 27/4 + 3/1
    4x >= 27/4 + 12/4
    4x >= 39/4
    HP = { x| -15/16 >= x >= 39/4 }

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