Matematika

Pertanyaan

hasil dari x/3+y/3-z=7 dan x/4-3y/2+z/2=-6 dan x/6-y/4-z/3=1

1 Jawaban

  • (x/3 + y/3 - z = 7) + (x/4 - 3y/2 + z/2 = -6) + (x/6 - y/4 - z/3 = 1)
    (x/3 + x/4 + x/6) + (y/3 - 3y/2 - y/4) + (-z/1 + z/2 - z/3) = 7 - 6 + 1
    (4x/12 + 3x/12 + 2x/12) + (4y/12 - 12y/12 - 3y/12) + (-6z/6 + 3z/6 - 2z/6) = 2
    (10x/12) + (-11y/12) + (-5z/6) = 2
    10x/12 - 11y/12 - 10z/12 = 2

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