Luas selimut kerucut 550cm² jari2 alas 7cm.hitung a.panjang garis pelukisnya b.luas permukaan kerucut

luas selimut kerucut= πrs
<=> 550 = 22/7 x 7 x s
<=> 550 = 22 x s
<=> s = 550:22
<=> s = 25 cm
luas permukaan kerucut = πr^2+πrs
= 22/7 x 7 x 7 + 22/7 x 7 x 25
= 154 + 550
= 704 cm^2