Volume sebuah kerucut 3.696 cm dan tingginya 18 cm. Panjang jari jari alas kerucut adalah....cm

V. kerucut = 1/3.π.r².t
3.696 = 1/3 . 22/7 . r² .18
3.696 = 6 . 22/7 . r²
3.696 = 132/7 . r²
r² = 3.696 : 132/7
r² = 3.696 x 7/132
r² = 28 x 7
r² = 196
r = √196
r = 14 cm

Diket:v.kerucut=3696
t=18

V.kerucut= ⅓.π.r².t
r²=⅓.3696:22/7.18
r²=⅓.22.528.18
r²=22.528.6
r²=69696
r=√69696=264