0,5'log(2x-8)≤ -1 HP= ?
Matematika
tehodorr999
Pertanyaan
0,5'log(2x-8)≤ -1
HP= ?
HP= ?
1 Jawaban
-
1. Jawaban qmase
0,5 = 1/2 = 2^-1
(-1) 2'log(2x-8) <= - 1
2'log(2x-8) >= 1
2'log(2x-8) >= 2'log2
2x-8>=2
2x>=10
X>=5
Jangan lupa syarat log
2x-8>=1
2x>=9
X>=4,5
Jadi Hp = {x| x>= 5, x € R}