nilai x yang memenuhi persamaan 4/5(2 3x-2)+8x/20=1

Pembahasan :
4/5(2³ˣ¯²) + 8ˣ/20 = 1

Kalikan 20 kedua ruas
4/5 . 20(2³ˣ¯²) + 8ˣ/20 . 20 = 20
16(2³ˣ¯²) + 8ˣ = 20
16(2³ˣ¯²) + 2³ˣ = 20

Misal 2³ˣ = a
16(a/4) + a = 20
4a + a = 20
5a = 20
a = 4

Substitusi...
a = 4
2³ˣ = 4
2³ˣ = 2²
3x = 2
x = 2/3