p log√32+p log 1/√2=2 tentukan nilai p

P log 32^1/2 + P log 2^-1/2=2 
1/2 P log 32 -1/2 P log 2=2 
1/2 P (log 32 - log 2)=2 
P (log 32/2) = 2*2 
P(log 16)=4 
P = 4/log16 
P= 3,32

P log √32+p log 1/√2=2
P log √32.1/√2 =2
P log √32/√2=2
P log √16 =2
P log 4=2
2 log 4=2
Jadi jawabannya p adalah 2